in an expression
(8/9) squared (-81)+3/5dividedby-9/10

+0

(1) Answers

Skyheart

If you wanted to calculate it, there it is:
[latex](\frac{8}{9})^2 (-81)+\frac{\frac{3}{5}}{\frac{-9}{10}} = \frac{64}{81}*(-81)+\frac{3}{5}*\frac{10}{-9} = -64+\frac{-2}{3}= \\ =-64-\frac{2}{3}=\frac{-192-2}{3}=\frac{-194}{3}[/latex]