Requestion data with python script

[Oconnor 0]

Hello,

 

If this is the wrong forum, just move it accordingly. 

 

I am trying to request some data to display it own my own custom home automation website, but i'm fairly new to all this so i've hit an error I don't quite understand. I've tried to google and use the search function, maybe my keywords are wrong, but I can't find any info that I understand.

What I am trying to do is show the 5 latest added media with a python script, I've done it like so:

 

import eg
import urllib, urllib2

url = 'http://10.0.0.112:8096/emby/Items/Latest?Limit=5&Fields=PrimaryImageAspectRatio%2CBasicSyncInfo&ImageTypeLimit=1&EnableImageTypes=Primary%2CBackdrop%2CThumb'
values = {}
data = urllib.urlencode(values)
apikey = ('***Hidden it***')

try:
    req = urllib2.Request(url, data)
    req.add_header('X-MediaBrowser-Token', apikey)
    
    response = urllib2.urlopen(req)
    result = response.read()
    response.close()
    print result

except (urllib2.URLError, IOError), e:
    print e

I know this must be off, but it throws me an error:
 

HTTP Error 400: FormatException

I'm not sure how to proceed, am I doing all of this wrong? The access key is needed maybe?

Edited December 1, 2016 by Eirik226

[mastrmind11 722]

Hello,

 

If this is the wrong forum, just move it accordingly. 

 

I am trying to request some data to display it own my own custom home automation website, but i'm fairly new to all this so i've hit an error I don't quite understand. I've tried to google and use the search function, maybe my keywords are wrong, but I can't find any info that I understand.

 

What I am trying to do is show the 5 latest added media with a python script, I've done it like so:

 

 

import eg
import urllib, urllib2

url = 'http://10.0.0.112:8096/emby/Items/Latest?Limit=5&Fields=PrimaryImageAspectRatio%2CBasicSyncInfo&ImageTypeLimit=1&EnableImageTypes=Primary%2CBackdrop%2CThumb'
values = {}
data = urllib.urlencode(values)
apikey = ('***Hidden it***')

try:
    req = urllib2.Request(url, data)
    req.add_header('X-MediaBrowser-Token', apikey)
    
    response = urllib2.urlopen(req)
    result = response.read()
    response.close()
    print result

except (urllib2.URLError, IOError), e:
    print e

I know this must be off, but it throws me an error:

 

HTTP Error 400: FormatException

I'm not sure how to proceed, am I doing all of this wrong? The access key is needed maybe?

Try encoding the URL you're passing.  ie, & should be %26, and so on

[Oconnor 0]

Tried that - gave me the same error - I did find this tho:

 

Add the following request header on every request:

Authorization=MediaBrowser UserId="e8837bc1-ad67-520e-8cd2-f629e3155721", Client="Android", Device="Samsung Galaxy SIII", DeviceId="xxx", Version="1.0.0.0"

But i'm not sure how I would do that here, mind giving a quick example? 

[mastrmind11 722]

Tried that - gave me the same error - I did find this tho:

 

 

Add the following request header on every request:

Authorization=MediaBrowser UserId="e8837bc1-ad67-520e-8cd2-f629e3155721", Client="Android", Device="Samsung Galaxy SIII", DeviceId="xxx", Version="1.0.0.0"

But i'm not sure how I would do that here, mind giving a quick example? 

I've never used the API and years since I've used Python, but I think that means to literally add that info to the request header as key/value pairs.  So like:

import urllib2
req = urllib2.Request('http://www.example.com/')
req.add_header('param1', '212212')
req.add_header('param2', '12345678')
req.add_header('other_param1', 'sample')
req.add_header('other_param2', 'sample1111')
req.add_header('and_any_other_parame', 'testttt')
resp = urllib2.urlopen(req)
content = resp.read()

http://stackoverflow.com/questions/7933417/how-do-i-set-headers-using-pythons-urllib

[Oconnor 0]

I see! Thank you - I'll look more into it today, thanks for the help